MCQ Answers

1. The attainment of individual and organisational goals is mutually interdependent and linked by a common denominator - employee work motivation. Organisational members are motivated to satisfy their personal goals, and they contribute their efforts to the attainment of organisational objectives as means of achieving these personal goals. The passage best supports the statement that motivation Answer: encourages an individual to give priority to personal goals over organisational goals.  2. Though the waste of time or the expenditure on fashions is very large, yet fashions have come to stay. They will not go, come what may. However, what is now required is that strong efforts should be made to displace the excessive craze for fashion from the minds of these youngsters. The passage best supports the statement that: Answer: the hoard for fashion should be done away with so as not to let down the constructive development. 3. Satisfaction with co-workers, promotion opportunities, the natu

1. Choose the option to replace the question mark in the below number series. 4, 9, 19, 34, 54, ?, 109 Answer: 79 Solution: The difference between adjacent terms is like 5,10,15,20,25,30,35 and so on. So 54+25=79 2. Choose the option to replace the question mark in the below number series. 5, 3, 6, 2, 7, 1, ? Answer: 8 Solution: Two sequences are intermingled. First sequence at odd positions is like 5,6,7,... Second at even positions is like 3,2,1,... So ? = 8 3. Choose the option to replace the question mark in the below number series. 5, 4, 9, 81, 79, 320, 20, 11, ? Answer: 279 Solution: For every three terms, third is the difference between square of first term minus square of second term 9 = 5^2 - 4^2, 320 = 81^2 - 79^2. ? = 20^2 - 11^2 = 279 4. Choose the option to replace the question mark in the below number series. 1, 3, 6, 11, 18, 29, ? Answer: 42 Solution: Starting from 1, the prime numbers from 2 are added to get the next term. 1 + 2 =3, 3 + 3 =6, 6 + 5 =11 and so on. So ? =

1. The children are very quiet. I hope they are not getting _____ anything they should not be. Answer: up to 2. I thought my Maths book was lost, and I ______ it all over the house. Answer: looked for 3. I have been studying hard, I hope to ________ my English exam. Answer: get through 4. After my little brother was born, my parents told me that I would have to ______ him. Answer: look after 5. After the hostages had been in captivity for two weeks, the terrorists finally decided to ______ to the police. Answer: give themselves up 6. They got married so young that it is hardly surprising it did not work _____ . Answer: out 7. Dave is very happy because his daughter has just got _____ a good university. Answer: into 8. At the political demonstration the activists were busy _____ tracts against the government. Answer: giving out 9. Your plane _______ at 5.40 am, sir. Answer: took off  10. I thought it was a greatreat little restaurant, but for some reason, it just did not catch _____ . A

 1. How many terms are there in the expansionof (a+b+c)^10 ? Answer: 66 Solution: This is like distributing 10 power among three groups. Hence number of terms = n+r-1 C r-1 = 10+3-1 C 3-1 = 12C2 = 66 2. How many 5-digit numbers can be formed using the digits 1, 2, 3, 4 and 5 without repetition? Answer: 120 Solution: Since all the five digits are distinct and all of these are used, the result should be 5! = 120. 3. If words are formed with letters in the word SHUVANK and arranged in alphabetical order in a dictionary, find the 55th word in the dictionary? Answer: AHSNKUV Solution: First arrange the letters in alphabetical order. A H K N S U V   Now total words possible with each letter in the beginning is = (7-1)! = 720. As 55 is less than 720, the starting letter is A.   Now 55 is more than 4! but less than 5!. So AH will be the first two letters which will be followed by 120 combinations with KNSUV   Starting with AHK - we will have 24 words Then starting with AHN - we will have 24 wo

1. There are 7 employees in a company and three are selected to do a task every day. This repeats as long as a distinct group can be formed, that is the combination of three employees in the group has never repeated (formed earlier). How many times can an employee be selected in a group? Answer: 15 Solution: Let us consider any one employee X. X can be paired with any two employees from the remaining 6. Hence required num of times = 6C2 = 15 2. A football team consists of 16 players. It includes 2 strikers and 5 mid-fielders. In how many ways can a playiing eleven be selected if we have to select 1 forward keeper and at least 4 mid-fielders? Answer: None of these Solution: Ans: None of the above (As answer is 1092) Num of ways of selecting a forward = 2C1 = 2. Atleast 4 mid-fielders means it can be 4 or also 5. When it is 4 mid-fielders, Num of ways to pick the team = 2C1 * 5C4 * 9C6 = 2*5*84 = 840 When it is 5 mid-fielders, Num of ways to pick the team = 2C1 * 5C5 * 9C5 = 2*1*126 = 25

 1. How many 3-digit numbers can be formed from the digits 1, 3, 5, 6, 7 and 9, which are divisible by 5 and none of the digits is repeated? Answer: 20 Solution: To be divisible by 5, 5 should be in the unit digit (as no zero is given). Hence number of ways = 5*4*1 = 20 2. If the letters of the word 'MOTHER' are written in all possible order and these words are written out as in dictionary, find the rank of the word 'MOTHER'. Answer: 309 Solution: The letters in alphabetical order are E H M O R T. Words beginning with E and H = 120+120 = 240 Words beginning with ME and MH are = 24+24 = 48 Words beginning with MOE, MOH, MOR = 6+6+6 = 18 Words beginning with MOTE = 2 Hence rank of MOTHER = 240+48+18+2 + 1 = 309 3. In how many ways can 9 books be divided equally among 3 boys? Answer: 12!/(24^3) Solution: Number of ways of distributing 12 distinct items, into 3 groups of size 4 = 12!/((4!)^3) = 12!/(24^3) 4. In a group of 6 men and 4 women, four people are to be selected. I

 1. A student multiplies a number by 9/5 instead of multiplying it by 5/9. What is the percentage change in the resulting value due to this mistake? Answer: None of these Solution: Let the number be n. Expected result = 5n/9 Obtained result = 9n/5 Difference = 9n/5 - 5n/9 = 56n/45 Percentage change = 100 * (56n/45)/(5n/9) = 224% 2. A dosa shop increased the price of a dosa from Rs.20 to Rs.25. By what percentage should a customer decrease his dosa consumption to keep the food expense constant? Answer: 20% Solution: Increase in price ratio = x = (25-20)/20 = 1/4. Hence decrease in consumption ratio = y = x/(1+x) = 1/4/(1+1/4)= 1/5. Let original food expense be F. % decrease = 100*(F/5)/F = 20%. 3. 5000 voted in an election between two candidates. 14% of the votes were invalid. The winner won by a margin approximately closer to 15%. Find the number of votes secured by the winner. Answer: 2473 Solution: Valid votes = 5000 * 86/100 = 50*86 = 4300 Let num of votes got by winner = w. Votes g

1. If 245% of x is 986 what is (x% of 245) + 90? Answer: 1076 Solution: x% of y is equal to y% of x. As 245% of x = 986, x% of 245 = 986. Hence (x% of 245) + 90 = 986+90 = 1076 2. After the new CEO took over, the revenue of the company increased by 50% every quarter. If the difference in the revenue between second and third quarter after the CEO took over was 450 millions, what was the third quarter revenue? Answer: 1350 millions Solution: Let the revenue at the end of second quarter be x. Revenue at the end of third quarter is x + x*50/100 = 1.5x The difference 1.5x - x = 0.5x = 450, Hence x=900 millions. Revenue at the end of third quarter = 1.5x = 1.5*900 = 1350 millions. 3. A student multiplies a number by 5 instead of dividing it by 5. What is the percentage change in the resulting value due to this mistake? Answer: 2400% Solution: Let the number be n. Expected result = n/5 Obtained result = 5n Difference = 5n - n/5 = 24n/5 Percentage change = 100 * (24n/5)/(n/5) = 2400% 4. If x%

 1. The price of a bag was first increased by 10% and then again by 20%. If the final price was Rs.33, the original price of the bag was Answer: Rs. 25 Solution: Let original price be x. The final price is x * 1.1 * 1.2 = 33 Solving x = 25 2. If 75% of a number is added to 75, the result is the same number. The number is Answer: 300 Solution: Let number be x. 75x/100 + 75 = x, x = 300 3. When the price of sugar decreases by 10%, a man could buy 1kg more for Rs.270. The original price of sugar is Answer: Rs.30 Solution: Decrease in price of 10% on 270 = Rs.27 which is the price of 1kg sugar at reduced price. So original price = Rs.30 (increase of 10% on Rs.27) 4. The price of a bag was first increased by 10% and then again by 20%. If the last increment in price was Rs.33, the original price of the bag was Answer: Rs.150 Solution: Let original price be x. 1.1x and 1.1x*1.2 are the prices. Now 1.1x*1.2 - 1.1x = 33, 1.1x(1.2-1) = 33, x = 33/0.2 * 1.1 = 150 5. A fruit seller had some apples

 1. To learn is to understand the world.  2. The trip to the city is neither long nor expensive. 3. My English is improving slowly but surely. 4. You must either stay home or go with us. 5. Diana was combing her hair, 6. We are not for war but for peace. 7. John supports the idea because, first, it is simple; second, it is unique. 8. This car is not only fast but also safe. 9. My sister likes singing and reading. 10. She played basketball, had a shower and went to school. 11. Maria tried holding her breath, chewing a piece of gum, and poking her belly, but she could not quiet her empty stomach, which rumbled during the exam. 12. and were quite determined to do a great job. 13. We found the film repulsive, offensive, and embarrassing. 14. Maina brewed coffee, steamed milk and sang a song as she prepared food. 15. You can join either the army or the navy. 16. Nadiya likes playing the piano, the trumpet and the guitar. 17. In counseling, I think both talking and listening are important. 1

 1. Choose the word which is similar in meaning to the definition below. A person who speaks many languages Answer: Polyglot 2. Choose the correct answer Murder of a child Answer: Infanticide 3. Choose the word which is similar in meaning to the definition below. Something that relates to everyone in the world Answer: Universal 4. Select the option that can be substituted for the given sentence. Chatter rapidly and unintelligibly. Answer: Jabber 5. Choose the most suitable 'one word' for the following expression given below: Easily cheated or duped Answer: Gullible 6. Choose the correct answer which will act as a one word substitute for Incapable of being corrected or reformed Answer: Incorrigible 7. Choose the word which means the same as the definition below. One who is fond of fighting Answer: Bellicose 8. In question given below out of four alternatives, choose the one which can be substituted for the given word/sentence. A place where monks live as a secluded community Ans

1. A number consists of 3 digits whose sum is 10. The middle digit is equal to the sum of the other two. If 99 is added to the number the digits are reversed. Find the last two digits of the number. Answer: 53 Solution: Ans: 53 (as the number is 253). Let the number be xyz. x+z=y. Hence 2y=10, y=5. As x+z=5, the x and z can be (0,5) (1,4), (2,3). The numbers can be 055, 154, 253. Among these three numbers only 253 is reversed when 99 is added to it. 2. What is the unit digit of the expression 8^56 - 2^56 ? Answer: None of these Solution: Ans: None of the above (as answer is 0) If n is even x^n - y^n is always divisible by (x+y). Hence the expression is divisible by 8+2 = 10 which implies the unit digit is zero. 3. How many numbers are divisible by 3, 5, 7 between 11000 and 22000 inclusive ? Answer: 105 Solution: To be divisible by 3, 5, 7, it should be divisible by their LCM 105 The first number divisible within the given range is 11025 The arithmetic progression is like 11025, 11130

 1. How many numbers are there between 500 and 600 containing atleast one 9? Answer: 19 Solution: When 9 is in unit digit, possible numbers = 10 * 1 = 10 When 9 is in tens digit, possible numbers = 1 * 10 But 599 is common and hence repeated twice. Total = 10+10-1 = 19 2. Find the number of prime factors of 6^10 * 7^17 * 55^27. Answer: 91 Solution: 6^10 * 7^17 * 55^27 = 2^10 * 3^10 * 7^17 * 5^27 * 11^27 So prime factors = 10+10+17+27+27 = 91  3. If a positive integer N is divisible by 44 it is also divisible by Answer: 11 Solution: 44 = 2*2*11. Hence 1,2,4,11,22,44 are it's factors. Among the given options, 11 is the answer. 4. Find the unit digit of 1544^56781298 Answer: 6 Solution: For a number ending with 4, even power gives six as unit digit and odd power gives 4 as unit digit. As 56781298 is even, the unit digit is 6. 5. Find the remainder when 43^23 + 37^23 is divided by 40. Answer: 0 Solution: 43^23 mod 40 = 3^23 mod 40 37^23 mod 40 = (-3)^23 mod 40 (Using remainder theorem)

 1. Find the remainder when 3^126 is divided by 8. Answer: 1 Solution: 3^126 = 9^63. Hence remainder = remainder of (9/8) ^ 63 = 1^63 = 1 2. What is the remainder when 4^82 is divided by 6? Answer: 4 Solution: Remainder of 4^n mod 6 is 4 irrespective of the value of n, where n > 0. 3. Find the last two digits in 4761^25 Answer: None of these Solution: The unit digit will be 1. The tens digit will be the unit digit in the product of 6*5(the unit digit in power and the tens digit of the number) = unit digit in 30 = 0 Hence last two digits will be 01 4. If you wrote all of the numbers from 300 to 400 on a piece of paper, how many times would you have written the number 3? Answer: 120 Solution: Numbers from 300 to 399 will have 100 3's in hundredth position. They will have 10 3's in tenth position (from 330 to 339) and 10 3's in unit position (for 303,313,....,393). Hence overall 120. 5. Which of the following divides the difference between cubes of two consecutive positive

1. A two-digit number when read from left to right, is 4.5 times less than the same number read from right to left. What is the first digit of the number? Answer: 1 Solution: Let the number be xy. 4.5 * (10x+y) = 10y + x, 9/2 * (10x+y) = 10y + x, 90x+9y = 20y + 2x, 88x = 11y, 8x=y. As x has to be chose from 1 to 9, (zero cannot be in most significant digit), the possible combinations are (1,8). Thus the number is 18 and the first digit is 1. 2. Find the highest power of 10 in 120! Answer: 28 Solution: Using formula to find num of zeros, highest power = 120/5 + 120/25 = 24+4 =28 3. What is the value of the below expression? (552*552 + 1600 - 220800) / (552*552*552 + 64000000) Answer: 1/952 Solution: The expression can be written as (552*552 + 400*400 - (552 * 400)) / (552*552*552 + 400*400*400). Using the formula,  (a2 + b2 - ab)(a+b) = (a3 + b3) the expression becomes, 1/(552+400) = 1/952 4. If a number 774958A96B is to be divisible by 8 and 9, the values of A and B, respectively, will