22-08-2021 Answers

 1. The price of a bag was first increased by 10% and then again by 20%. If the final price was Rs.33, the original price of the bag was

Answer: Rs. 25

Solution: Let original price be x.

The final price is x * 1.1 * 1.2 = 33

Solving x = 25


2. If 75% of a number is added to 75, the result is the same number. The number is

Answer: 300

Solution: Let number be x.

75x/100 + 75 = x,

x = 300


3. When the price of sugar decreases by 10%, a man could buy 1kg more for Rs.270. The original price of sugar is

Answer: Rs.30

Solution: Decrease in price of 10% on 270 = Rs.27 which is the price of 1kg sugar at reduced price.

So original price = Rs.30 (increase of 10% on Rs.27)


4. The price of a bag was first increased by 10% and then again by 20%. If the last increment in price was Rs.33, the original price of the bag was

Answer: Rs.150

Solution: Let original price be x.

1.1x and 1.1x*1.2 are the prices.

Now 1.1x*1.2 - 1.1x = 33,

1.1x(1.2-1) = 33,

x = 33/0.2 * 1.1 = 150


5. A fruit seller had some apples. He sold 40% of them and was left with 420 apples. How many apples did he have initially?

Answer: 700

Solution: Let total num of apples be x.

As 40% were sold, 60% remain.

0.6x = 420, x = 700


6. A candidate scores 25% and fails by 60 marks, while another candidate scores 50% marks, gets 40 marks more than that of the minimum required marks to pass the exam. The maximum marks for the exam is

Answer: 400

Solution: Let max marks be x.

0.25x + 60 = 0.5x -40,

x=400


7. What option should replace ? in the following expression?

550 / (? % of 500) = 2.5

Answer: 44

Solution: ? % of 500 = 550/2.5 = 220

? * 500/100 = 220

? = 44


8. In an offer 5 tickets can be purchased for the price of 3 tickets. If 5 tickets are purchased at the sale, the amount saved will be what percent of the original price of the 5 tickets?

Answer: 40%

Solution: Let original price of a ticket be x.

Original price for 5 tickets = 5x.

Discounted price = 3x.

Savings = 5x-3x = 2x.

Hence reqd % = 100 * 2x/5x = 40%


9. Due to an increase of 30% in the egg price, 6 eggs less are available for Rs.7.80. The price of eggs per dozen is

Answer: Rs 4.68

Solution: Let earlier price per egg be x.

7.80/x - 7.80/1.3x = 6

Solving x=7.80/1.3 * 0.3/6 = 0.3

Current price per egg = 1.3*0.3 = 0.39

Price per dozen = 12*0.39 = Rs 4.68


10. If 7% of A is 42, then what is 27% of A ?

Answer: 162

Solution: 7*A/100 = 42, So A/100 = 42/7

We need 27*A/100 = 27*42/7 = 27*6 = 162


11. A vessel is filled with milk. 80% of the milk is replaced with water. This process is repeated thrice. Find the percentage of milk in the end.

Answer: 51.2%

Solution: Final % = 100 * (80/100)^3 = 51.2%


12. 4% is equal to one out of every

Answer: 25

Solution: 4% = 4/100 = 1/25.

Hence it is one out of every 25.


13. Two numbers are 10% and 25% more than third number. What percent is the first of the second?

Answer: 88%

Solution: Let third number be x.

First num = 1.1x

Second num = 1.25x

Reqd % = 100 * 1.1x/1.25x = 88%


14. After spending 25% of his money and donating Rs.10 to a beggar, a man had Rs.14 left. How much did he have initially?

Answer: Rs.32

Solution: Let the money he had initially be x.

Money left after spending 25% of his money= 14+10 = Rs.24

x - 0.25x = 24, x=32


15. Due to an increase of 20% in the egg price, 4 eggs less are available for Rs.24. The revised price of eggs per dozen is

Answer: Rs 14.40

Solution: Let earlier price per egg be x.

24/x - 24/1.2x = 4

Solving x=24/1.2 * 0.2/4 = 1

Current price per egg = 1.2*1 = 1.2

Price per dozen = 12*1.2 = Rs 14.40

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