23-10-2021 Answers

 1.She was being threatened by him about her future

2.A ticket will, You will be given

3.Briyani is cooked by her every Sunday.

4.Everybody drinks water

5.The women have not cleaned the cans not well.

6.Your shoes need to be cleaned properly.

7.were being read out by the teachers.

8.The dog was hit with a stick

9.The mason is building the wall

10.I remember being taken...

11.Do you want someone...

12.Why was such a letter...

13.A perfect dam has been...

14.By whom, Who were, By whom were

15.I remember being taken...

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14-08-2021 Answers

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21-07-2021 Answer

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 216 cubes of similar size are arranged in the form of a bigger cube. The six faces of the bigger cube are painted with green, red, blue, violet, white, pink colours. Related Comprehension Questions 1. How many cubes are painted with red or blue? Answer: 66 or 72 Solution: In one face 36 smaller cubes will be present. When red and blue are not adjacent 36*2=72 cubes will be painted with red or blue. When these colours are in adjacent faces, the six common cubes are to be subtracted giving 72-6=66 2. How many cubes are painted with red or blue or green? Answer: 91 or 96 Solution: When all three colours are adjacent to each other, we get 36 + 30 + 25 = 91 (We subtract the common cubes from 36 and hence 30 and 25) When one of the three colours is in between the other two, we get 36+30+30 = 96 3. How many cubes are painted with red or blue but not green? Answer: 55 or 60 Solution: When all three colours are adjacent to each other, we get 30+25 = 55 When green coloured face is in betwee...
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13-09-2021 Answers

1. If Rs.24586 is to be divided among four persons A,B,C,D such that A:B = 3:4, B:C = 5:6 and C:D = 7:5, who will get the minimum amount? Answer: Person A Solution: A/B = 3/4     B/C = 5/6   C/D=7/5 Shortcut: The ratio of A:B:C:D is given as (n1*n2*n3) : (d1*n2*n3) : (d1*d2*n3) : (d1*d2*d3). Hence A:B:C:D = (3*5*7):(4*5*7):(4*6*7):(4*6*5) = 105:140:168:120 Hence A will get minimum amount. 2. Three cans contain equal quantities of alcohol and water in the ratios  6:1, 5:2 and 8:3 respectively. If the contents of all three cans are poured into a single vessel, the proportion of alcohol:water in the vessel is Answer: 59:18 Solution: Let the quantity of alcohol and water be 6x:x , 5y:2y and 8z:3z. Proportion of alcohol:water = (6x+5y+8z)/(x+2y+3z). --Eq1 As all the cans contain equal quantities of alcohol and water, 7x = 7y = 11z. Hence x=y and z=7y/11. Substituting in Eq1), the required proportion is (6y + 5y + 56y/11)/(y + 2y + 21y/11) = 177y/54y = 59:18 3. A...
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